Question

8. A 20 degree caudal angle was used on a particular AP exam. If the patient had to be imaged with a PA projection, how would the angle change to produce the same image

Answer 1

An object moving from 20 cm to 5 cm away from a concave mirror, which initially produced an inverted, equal-sized image, will result in a virtual, upright, and enlarged image since it's now within the focal length of the mirror.

Step-by-step explanation:

When we have an object at a distance of 20 cm from a mirror, and it forms an image that is inverted and equal in size, this typically describes the behavior of a concave mirror. Concave mirrors reflect light inward to one focal point, and where the object is placed concerning the focal point determines the nature of the image seen.

If we move the object closer to the mirror, at a distance of 5 cm, the mirror's focal length has not changed, but the object's distance to the mirror is now less than the focal length. In the case of a concave mirror, if the object is within the focal length, the image formed is virtual, upright, and enlarged. Therefore, when the object is placed at 5 cm from the mirror, assuming the focal length is between 5 cm and 20 cm, the image will appear larger and upright as compared to when the object was at 20 cm.

Answer 2

The answer is "5 or 35".

Step-by-step explanation:

It also is important to understand the difference in the AP and PA predictions, and we will talk regarding their difference, and maybe we'll take the circumstances.

It is called the PA view during the process of x-ray and as the x-ray passes from its body back to both the foreground.

Its direction was its reverse throughout the AP view. Now let's understand what critical it's really. So less the distance among object and display was also created, much clears the shadow, and according to physics concepts x-ray was its light source in this instance, but we're the target. In AP display's the rear side, which means good shadow, whereas the implications of alternative give better shadow in the PA view.

If talking around the same picture, the angle difference between both the AP and the PA visual is maximum of 15-20°.

Its situation indicates a caudal angle of 20° for the AP test. So, it must be for PA:

`\to 20(\pm) 15 \\\\\to 20+ 15 \ \ \ \ or \ \ \ \ \to 20-15 \\\\\to 35 \ \ \ \ or \ \ \ \ \to 5 \\\\`