Question

What is an equation of the line that passes through the points (-6,2) and (6,-2)

Answer 1

y = -1/3 x + 8/3 or 3y = -x + 8

Explanation:

m = (-2 - 2) / [(6 - (-6)]

= -4 / 12

= -1/3

Use (-6, 2) and substitute in the formula:

y = mx + b

2 = -1/3 (2) + b

2 = -2/3 + b

2 + 2/3 = b

8/3 = b

y = mx + b

y = -1/3 x + 8/3 or 3y = -x + 8