Question

Pls Help, Max Points

Answer 1

`\\ \rm\Rrightarrow (2)/(x+3)-(1)/(x-3)=(-7)/(x^2-9)`

`\\ \rm\Rrightarrow (2(x-3)-1(x+3))/((x+3)(x-3))=(-7)/(x^2-9)`

`\\ \rm\Rrightarrow (2x-6-x-3)/(x^2-9)=(-7)/(x^2-9)`

`\\ \rm\Rrightarrow (x-9)/(x^2-9)=(-7)/(x^2-9)`

`\\ \rm\Rrightarrow x-9=-7`

`\\ \rm\Rrightarrow x=9-7`

`\\ \rm\Rrightarrow x=2`

Answer 2

x = 2

Explanation:

`\large \begin{aligned}(2)/(x+3)-(1)/(x-3) & = (-7)/(x^2-9)\\\\(2(x-3))/((x+3)(x-3))-(1(x+3))/((x+3)(x-3)) & = (-7)/((x+3)(x-3))\\\\(2(x-3)-(x+3))/((x+3)(x-3)) & = (-7)/((x+3)(x-3))\\\\(x-9)/((x+3)(x-3)) & = (-7)/((x+3)(x-3))\\\\x-9 & = -7\\\\x&=-7+9\\\\x & = 2\end{aligned}`