Step-by-step explanation:
Empirical formula is the forrmula that shows the relative number of atoms present in a compound. It is also referred to as the simplest formular of a compound.
a) C6H12O6
The atoms of the elements present are in ratio; 6:12:6
After simplifying by dividing by the highest common factor (6) we have;
6/6 : 12/6 : 6/6 = 1 : 2 : 1
The empirical formula is CH2O
b) Na2C2O4
The atoms of the elements present are in ratio; 2:2:4
After simplifying by dividing by the highest common factor (2) we have;
2/2 : 2/2 : 4/2 = 1 : 1 : 2
The empirical formula is NaCO2
c) Na3PO4
The atoms of the elements present are in ratio; 3:1:4
After simplifying by dividing by the highest common factor (1) we have;
3/1 : 1/1 : 4/1 = 3 : 1 : 4
The empirical formula is still Na3PO4.
d) C2H4O2
The atoms of the elements present are in ratio; 2:4:2
After simplifying by dividing by the highest common factor (1) we have;
2/2 : 4/2 : 2/2 = 1 : 2 : 1
The empirical formula is CH2O
The names are;
a) Glucose
b) Sodium Oxalate
c) Trisodium Phosphate
d) Acetic Acid