Answer:
A. The car does not land in the river
B. 399.27 meters
Step-by-step explanation:
The Cliff Height, s: 609.6 m
The velocity at the edge of the cliff, vₓ = 40.3 meters/second (90 miles per hour)
The location of the Colorado River = 536.5 meters (1,760 feet) from the cliff base
The width of the river across = 300 feet average
The depth of the river = 40 feet
Assumption;
The direction of the vehicle = Horizontal
Vertical velocity of the vehicle = 0 m/s
The time, t, it takes the car to reach the level of the bottom of the cliff is given as follows;
s =
·t + 1/2·g·t²
Where;
= The initial vertical velocity of the vehicle = 0
g = The acceleration due to gravity = 9.81 m/s²
Therefore, we have;
609.6 = 0×t + 1/2 × 9.81 × t²
609.6 = 1/2 × 9.81 × t²
t = √(2 × 609.6/9.81) ≈ 11.148 seconds
The horizontal distance, x, travelled by the car in the above calculated, 11.148 seconds, time is x = vₓ × t = 40.3 × 11.148 = 449.27 meters
Therefore, the horizontal distance from the cliff travelled by vehicle on landing from the base of the cliff = 449.27 meters
Given the river is located approximately 536.5 meters from cliff's base, the car does not land in the river
B. In order for the car to land 50 ft. from the edge of the river, the river has to be 449.27 - 50 ≈ 399.27 meters from the base of the cliff.