Question

an object is traveling with a velocity of 3.05 m/s. the object then accelerates at 2.82 m/s^2 over a displacement of 18.4m. what is the final velocity? answer choices - 2.82m/s, 113.1m/s, 54.9m/s, 10.6m/s

Answer 1

Final velocity, V = 10.6 m/s

Step-by-step explanation:

Given the following data;

Initial velocity, U = 3.05m/s

Acceleration, a = 2.82m/s²

Displacement, S = 18.4m

To find the final velocity of the object, we would use the third equation of motion;

`V^(2) = U^(2) + 2aS`

Where;

• V represents the final velocity measured in meter per seconds.

• U represents the initial velocity measured in meter per seconds.

• a represents acceleration measured in meters per seconds square.

• S represents the displacement measured in meters.

Substituting the values into the equation, we have;

`V^(2) = 3.05^(2) + 2*2.82*18.4`

`V^(2) = 9.3025 + 103.776`

`V^(2) = 113.0785`

Taking the square root, we have;

V = 10.6 m/s

Therefore, the final velocity of the object is 10.6m/s.