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A plating company has two silver plating systems with variances σ12 and σ22. You, as the manager, desired to compare the variability in the silver plating done by System-1 with that done by System-2. An independent random sample of size n1= 12 of the System-1 yields s1 = 0.038 mil and sample of size n2= 10 of System-2 yields s2 = 0.042 mil. We need to decide whether σ12= σ22 with α = 0.05. What is the rejection region?

User Trang
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1 Answer

4 votes

Answer:

The rejection region is


F_(cal) < F_{{1-(\alpha)/(2)} , df_1 , df_2 }

or
F_(cal) > F_{{(\alpha)/(2)} , df_1 , df_2 }

and

From the value obtained we see that


F_(cal) < &nbsp; F_{(\alpha )/(n) , df_1 , df_2 } Hence

The decision rule

Fail to reject the null hypothesis

The conclusion

This no sufficient evidence to conclude that there is a difference between the two variance

Explanation:

From the question we are told that

The first sample size is
n_1 = &nbsp;12

The first sample standard deviation is
s_1 = &nbsp;0.038 \ &nbsp;mil

The second sample size is
n_2 = &nbsp;10

The first sample standard deviation is
s_2 = &nbsp;0.042 \ &nbsp;mil

The significance level is
\alpha =0.05

The null hypothesis is
H_o : \sigma^2_1 &nbsp;= \sigma^2_2

The alternative hypothesis is
H_o : \sigma^2_1 \\e &nbsp;\sigma^2_2

Generally the test statistics is mathematically represented as


F_(cal) = &nbsp;(s_1^2 )/(s_2^2)

=>
F_(cal) = &nbsp;( 0.038^2 )/(0.042^2)

=>
F_(cal) = &nbsp;0.81859

Generally the first degree of freedom is
df_1 = &nbsp;n_1 -1 &nbsp;= &nbsp;12-1 = 11

Generally the second degree of freedom is
df_2 = &nbsp;n_2 -1 &nbsp;= &nbsp;10 -1 = 9

From the F-table the critical value of
(\alpha)/(2) at the degrees of freedom of
df_1 = 11 and
df_2 =9 is


F_{(\alpha )/(n) , df_1 , df_2 } = &nbsp;3.91207

The rejection region is


F_(cal) < F_{{1-(\alpha)/(2)} , df_1 , df_2 }

or
F_(cal) > F_{{(\alpha)/(2)} , df_1 , df_2 }

and

From the value obtained we see that


F_(cal) < &nbsp; F_{(\alpha )/(n) , df_1 , df_2 } Hence

The decision rule

Fail to reject the null hypothesis

The conclusion

This no sufficient evidence to conclude that there is a difference between the two variance

User Prasanth J
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