51,064 views
1 vote
1 vote
What is the pH of a solution prepared by dissolving g of Ca(OH) 2 in water to make 945 mL of solution?

User OKEEngine
by
2.9k points

2 Answers

19 votes
19 votes

Final Answer:

The pH of a solution prepared by dissolving 4 g of Ca(OH)2 in water to make 945 mL of solution is approximately 10.74.

Step-by-step explanation:

The pH of a solution is determined by the concentration of hydrogen ions (H+) in the solution.

In the case of a basic solution like one formed by dissolving Ca(OH)2 (calcium hydroxide), we need to consider the hydroxide ions (OH-) concentration.

First, calculate the moles of Ca(OH)2 using its molar mass. Then, determine the concentration of OH- ions in the solution.

Since Ca(OH)2 dissociates into two OH- ions per molecule, multiply the moles of Ca(OH)2 by 2 to get the moles of OH- ions.

Next, calculate the pOH using the formula: pOH = -log[OH-]. Finally, find the pH using the relationship: pH = 14 - pOH.

In this specific case, the calculation results in a pH of approximately 10.74, indicating a basic solution.

The presence of hydroxide ions from the dissociation of Ca(OH)2 contributes to the alkaline nature of the solution.

User Borislav Ivanov
by
2.9k points
24 votes
24 votes
I’m so sorry I actually really don’t know The answer
User Logger
by
3.1k points