Question

The function h(x)=1/x^2+1 is the result of the composition f(g(x)). If g(x) = x^2+1,what is f(x)? A f(x)=1/square root x B f(x)=1/x C f(x)= 1/x+1 D f(x)=1/x^2+1

Answer 1

Answer: B. f(x)=1/x

Explanation:

Edge

Answer 2

Option B is correct

Explanation:

Given:
`h(x)=(1)/(x^2+1)` is the result of the composition
`f(g(x))`.

Also,
`g(x)=x^2+1`

To find:
`f(x)`

Solution:

Take
`f(x)=(1)/(x)`

Now check whether
`h(x)` is equal to
`f(g(x))` or not.

First find
`f(g(x))`

`f(g(x))=f(x^2+1)=(1)/(x^2+1)`

Also,
`h(x)=(1)/(x^2+1)`

Therefore,

`h(x)=f(g(x))`

So,

Option B is correct