Question

Train A is traveling at 70 mph to a destination 200 miles away. Train B will leave 20 minutes after train A. Train B will leave from Train A's destination and will head in Train A's direction. If Train B will be going at a speed 32 of Train A's, how long after Train A left will it take before Train B arrives at Train A's starting point? Round your answer to the nearest tenth of an hour

Answer 1

The answer is "2.2 h"

Explanation:

Speed of Train B:

`= (3)/(2) * 70 \ mph \\\\= 105 \ mph`

Train B is then moving on:

`= (200 \ miles)/( 105 \ mph) \\\\= 1.905 \ h\\`

Then it takes Train A to the left:

`\to 1.905\ h + 20 \ min \\\\= 1.905 \ h +0.333 \ h \\\\= 2.238 \ h`

To get train B to the reference point of train A = 2.2 h