19.4k views
0 votes
HELP ASAP TAKING A TEST I DONT KNOW HOW TO DO THESE I HAVE 1 HOUR PLEASE!

HELP ASAP TAKING A TEST I DONT KNOW HOW TO DO THESE I HAVE 1 HOUR PLEASE!-example-1
HELP ASAP TAKING A TEST I DONT KNOW HOW TO DO THESE I HAVE 1 HOUR PLEASE!-example-1
HELP ASAP TAKING A TEST I DONT KNOW HOW TO DO THESE I HAVE 1 HOUR PLEASE!-example-2
HELP ASAP TAKING A TEST I DONT KNOW HOW TO DO THESE I HAVE 1 HOUR PLEASE!-example-3
HELP ASAP TAKING A TEST I DONT KNOW HOW TO DO THESE I HAVE 1 HOUR PLEASE!-example-4
User Anjanette
by
7.6k points

1 Answer

4 votes

Answer:

diagonal is 11.14 cm

Explanation:

We start by writing the equation for the width (w) in terms of the length (L):

w = 2 L - 8

from the area = w * L = 62

we replace w in it: w * L = (2 L -8) * L = 62

2 L^2 - 8 L = 62

2 L^2 - 8 L - 62 = 0

extract 2 common factor:

2 (L^2 - 4 L - 31) = 0

Using quadratic formula we get:


L=(4+/-√(4^2-4(1)(-31)) )/(2) \\L=(4+/-√(140) )/(2)\\L=7.916\\or\\L=-3.916

So, we pick the positive answer L = 7.916 cm

Then we now know the with of the rectangle as well:

w = 2 * L - 8 = 2 * 7.916 - 8 = 7.832 cm

Now we estimate the diagonal of the rectangle using the Pythagorean theorem:


diag=√(7.916^2+7.832^2)\approx11.1356\,\,cm

which rounded to two decimal places is 11.14 cm

User JamesSugrue
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories