Question

What is the correct equation in vertex form for x^2+4x-12=0

Answer 1

`\boxed{(x+2)^2-16=0}`

Explanation:

`{}\quad x^2\,+\,4x\ -\ 12=0\\\\\underbrace{x^2+2\cdot x\cdot2+2^2}-2^2-12=0\\\\{}\qquad(x+2)^2\ \ -4-12=0\\\\{}\qquad(x+2)^2-16=0`