Question

3- The velocity-time graph below shows the motion of a

ball in free fall. What is the acceleration of the ball from
0.5 to 0.7 seconds? Show your work:

Answer 1

The acceleration of the ball from 0.5 to 0.7 seconds is 10 m/s²

Step-by-step explanation:

The data from the given velocity-time graph are as follows;

Velocity (meters per second)
`{}` Time (seconds)

0
`{}` 0.4

0.5
`{}` 0.45

1.
`{}` 0.5

1.5
`{}` 0.55

2.2
`{}` 0.6

2.5
`{}` 0.65

3.0
`{}` 0.7

3.5
`{}` 0.75

4.0
`{}` 0.8

4.5
`{}` 0.85

Therefore, the average acceleration of the ball from 0.7 to 0.7 seconds is given as follows;

Acceleration = (Change in velocity)/(Related change in time)

Acceleration = (3.0 - 1)m/s/(0.7 - 0.5)s = 2/0.2 m/s² = 10 m/s²

The acceleration of the ball from 0.5 to 0.7 seconds = 10 m/s².