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Determine the horizontal component of 40m at 330 degrees?

User Cemerick
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6.3k points

1 Answer

3 votes

Answer:


a_x=34.64\ m.

Step-by-step explanation:

Rectangular components of a vector

Given a vector
\vec a, the x-component and y-component of the vector are given respectively by:


a_x=|\vec a|.\cos\theta


a_y=|\vec a|.\sin\theta

Where
\theta is the angle measured with respect to the positive horizontal direction.

Let's calculate the horizontal component of a vector with magnitude 40 m and angle 330°


a_x=40\ m.\cos330^\circ


\boxed{a_x=34.64\ m.}

User Nastasha
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5.8k points