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What is the complete factorization of the polynomial function over the set of complex numbers?

f(x)=x3−5x2+4x−20



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User Karl Lorey
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1 Answer

3 votes

Answer:


x^3-5x^2+4x-20=(x-5)(x+2\mathbf{i})(x-2\mathbf{i})

Explanation:

Factorization of polynomials

Factor:


f(x)=x^3-5x^2+4x-20

There are several techniques to factor polynomials. We'll use algebraic manipulation and common factor:

Separate in groups:


(x^3-5x^2)+(4x-20)

Factor out 4 from 4x-20:


=(x^3-5x^2)+4(x-5)

Factor out
x^2 from
x^3-5x^2


=x^2(x-5)+4(x-5)

Factor out x-5:


=(x-5)(x^2+4)

The roots of


x^2+4=0

Are two complex numbers:


x=2\mathbf{i}, x=-2\mathbf{i}

The complete factorization is:


\boxed{x^3-5x^2+4x-20=(x-5)(x+2\mathbf{i})(x-2\mathbf{i})}

User Strugee
by
5.7k points