Question

Find the midpoint M of the line segment joining the points P = (3, - 7) and Q = (-7, 1).

Answer 1

Explanation:

Hey there!

The given points are; P(3,-7) and Q(-7,1)

Note: Use midpoint formula.

`midpoint(x</u><u>,</u><u>y</u><u>) = ((x1 + x2)/(2) </u><u>,</u><u> (y1 + y2)/(2) )`

Put all values.

`(x</u><u>,</u><u>y</u><u>) =( (3 - </u><u>7</u><u>)/(2) </u><u>,</u><u> ( - 7 + 1)/(2) )`

Simplify it.

`(x</u><u>,</u><u>y</u><u>) = </u><u>(</u><u>-</u><u>2</u><u> </u><u>,</u><u> - 3`)

Therefore, midpoint is (-2 ,-3).

Hope it helps...

Answer 2

The answer is (-2 , - 3)

Explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

`M = ( (x1 + x2)/(2) , \: (y1 + y2)/(2) ) \\`

where

(x1 , y1) and (x2 , y2) are the points

So we have

`m = ( (3 - 7)/(2) , ( - 7 + 1)/(2) ) \\ = ( - (4)/(2) , - (6)/(2) )`

We have the final answer as

( - 2 , - 3)

Hope this helps you