Question

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What is the equation of a line that passes through the point (9, −3) and is parallel to the line whose equation is 2x−3y=6?


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Answer 1

y = 2/3x - 9

Explanation:

Slope-Intercept Form: y = mx + b

m - slope

b - y-intercept

Step 1: Define

Point (9, - 3)

2x - 3y = -6

Step 2: Rewrite given equation

-3y = -2x - 6

y = 2/3x + 2

So our m = 2/3 (Parallel lines have the same slope but different y-intercepts)

Step 3: Find y-int of parallel line

y = 2/3x + b

-3 = 2/3(9) + b

-3 = 6 + b

b = -9

Step 4: Write parallel line equation

y = 2/3x - 9