60.1k views
0 votes
What is the solution of 5sin2θ=3 for 0≤θ≤2π? Please help.

What is the solution of 5sin2θ=3 for 0≤θ≤2π? Please help.-example-1

1 Answer

13 votes

Answer:

C)
\theta\approx\{0.3218,1.249,3.463,4.3908\}

Explanation:


5\sin2\theta=3;\: 0\leq\theta\leq 2\pi\\\\\sin2\theta=(3)/(5)\\ \\2\theta\approx\{0.6436,2.498,6.926,8.7816\}\\\\\theta\approx\{0.3218,1.249,3.463,4.3908\}

User Aaron Ray
by
5.9k points