Question

For what value(s) of k will the given relation not be a function?

M = { (15k+9, 4), (3·(4k−1), 6) }

Enter all possible values of k

Answer 1

Given:

The relation is

`M = \{ (15k+9, 4), (3\cdot (4k-1), 6) \}`

To find:

The value of k for which the relation is not a function.

Solution:

A relation is a function if their exist a unique output or y value for each input or x values.

A relation is not a function if it has two y-values for single x value.

So, the given relation is not a function if x-coordinates of both ordered pairs are equal.

`15k+9=3\cdot (4k-1)`

`15k+9=12k-3`

Isolate variable terms.

`15k-12k=-9-3`

`3k=-12`

Divide both sides by 3.

`k=-4`

Therefore, the given relation is not a function for k=-4.