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1 vote
What equation is graphed in this figure?

y-4= = -⅓(x+2)
y-3= ⅓(x + 1)
y+ 2 = -3(x - 1)
y - 5 = 3 (x - 1)​

What equation is graphed in this figure? y-4= = -⅓(x+2) y-3= ⅓(x + 1) y+ 2 = -3(x-example-1

2 Answers

4 votes

Answer:

y−5=3(x−1)

Explanation:

What equation is graphed in this figure? y-4= = -⅓(x+2) y-3= ⅓(x + 1) y+ 2 = -3(x-example-1
User Ravi Waghmare
by
4.4k points
3 votes

Answer:

y - 5 = 3(x - 1)

Explanation:

Let the equation of the line passing through a point (x', y') and slope 'm' is,

y - y' = m(x - x')

Since slope of a line passing through two points
(x_1, y_1) and
(x_2,y_2) is represented by,

m =
(y_2-y_1)/(x_2-x_1)

Therefore, slope of the line passing through (0, 2) and (1, 5) is,

m =
(5-2)/(1-0) = 3

Now equation of the line passing through a point (1, 5) and slope = 3 will be,

y - 5 = 3(x - 1)

Option (4) is the answer.

User Zeeshan Ahmad
by
4.4k points