How to solve 4x^2+100=0​

asked Feb 25, 2021 91.1k views

1 vote

How to solve 4x^2+100=0

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6 votes

(+)/(-) Answer:

x = ± 5i

Explanation:

How to solve 4x^2+100=0

4
x^(2) +100=0

4
x^(2) = -100

x^(2) 1=-100/4

x^(2) =-25

x = ±
√(-25)

x = ± 5i

Ajey answered Mar 3, 2021

by Ajey

4.8k points

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