Answer:
0.022m/s²
Step-by-step explanation:
Given
v = 10.22m/s
u = 9.78m/s
S = 200m
Using the equation of motion'
v² = u² + 2aS
v is the final velocity
u is the initial velocity
a is the acceleration
S is the displacement
Substitute the given parameters into the formula:
10.22² = 9.78² + 2a(200)
104.4484 = 95.6484 + 400a
400a = 104.4484 -95.6484
400a = 8.8
a = 8.8/400
a = 0.022m/s²
Hence the magnitude of his acceleration would have been 0.022m/s²