Question

How many grams of mgcl2 must be provided 1.89 mole of chloride ions

Answer 1

Mass = 89.97 g

Step-by-step explanation:

Given data:

Number of moles of chloride ions = 1.98 mol

Mass in grams of MgCl₂ present = ?

Solution:

we can see that 1 mole of MgCl₂ contain 2 moles of chloride ions. Thus 1.89 moles of chloride ions contain moles of MgCl₂ are,

Cl₂ : MgCl₂

2 : 1

1.89 : 1/2×1.89 = 0.945

Thus, 1.89 moles of chloride ions are provided by 0.945 moles of MgCl₂.

Mass of MgCl₂:

Mass = number of moles × molar mass

Mass = 0.945 mol × 95.211 g/mol

Mass = 89.97 g