Question

Part 2: Vertical Distance

1
do
2.942
d, = vertical distance
g = acceleration due to gravity (10m/s2)
t = time
How high was a brick dropped from if it falls in 2.5 seconds?
2.5 m
Ob
12.5 m
25 m
с
Od
31.25 m

Answer 1

31.25m

Step-by-step explanation:

Given parameters:

Acceleration due to gravity = 10m/s²

Time of drop = 2.5s

Unknown

Height of drop = ?

Solution:

To solve this problem, we must note that the brick was originally at rest. The appropriate motion equation to solve this is shown below;

H = ut +
`(1)/(2)`gt²

H is the height

u is the initial velocity

g is the acceleration due to gravity

t is the time taken

Input the parameters and solve;

H = 0 +
`(1)/(2)` x 10 x 2.5²

H = 31.25m