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In a survey of 439 teenagers in the US, 14% said that they worked during their summer vacation. a) What is the Margin of Error for this sample proportion

1 Answer

4 votes

Answer:


0.0166

Explanation:

Let the sample proportion be
\hat{p}=0.14 and the sample size be
n=439:


\displaystyle \text{Margin of Error}=\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\\\\\text{Margin of Error}=\sqrt{(0.14(1-0.14))/(439)}\\\\\text{Margin of Error}=\pm0.0166

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