Question

A class has 11 boys and 9 girls. Two of the students will be selected at random to serve on a committee. What is the probability that both of the selected students will be girls

Answer 1

`(18)/(95)\approx0.1895`

Explanation:

Because there's a
`(9)/(20)` chance of picking 1 girl, there will be a
`(8)/(19)` chance of picking another girl since there's one less girl.

Since the two events are independent, their probabilities are multiplied, so the probability of having 2 girls be selected to serve on the committee is
`(9)/(20)*(8)/(19)=(72)/(380)=(18)/(95)`.