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26 votes
26 votes
Pls hurry im on a time limit The spinner shown is divided into 6 equal sections

(two 4's, two 1's, one 3 and one 2.)
Enter the probability of the arrow stopping in a section labeled 2 on the first spin.

User Ikora
by
3.0k points

1 Answer

24 votes
24 votes

Answer: 1/6

Explanation:

We know the spinner is divided in 6 EQUAL sections.

The word "equal" means that if you spin the spinner, it gives all numbers a fair chance of being chosen. One section isn't larger or smaller than the other.

Knowing that, we can visualize this by drawing it out. (Shown in attachment below.)

We know that 2 sections of the spinner are labeled as 4, two sections are labeled as 1 one section labeled as 3 and one section labeled as 2. The probability of "2" being chosen is 1/6. Why? Because it only appears ONCE on the spinner. There is no other "2" on the spinner except that one 2. So, there is only 1 "2" available, we write that over the total number of sections. That is six. So, the final answer is 1/6.

Pls hurry im on a time limit The spinner shown is divided into 6 equal sections (two-example-1
User Nigong
by
2.8k points
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