Question

If 2000 kg cannon fires 2 kg projectile having muzzle velocity 200 m/s then the KINETIC ENERGY of the projectile will be ("E4" means "*10^4") *

1 point
4E4 J
1E4 J
1E3 J
None of the above

Answer 1

`K=4* 10^4\ J`

Step-by-step explanation:

Given that,

Mass of cannon is,M = 2000 kg

Mass of projectile, m = 2 kg

Velocity of the projectile, v = 200 m/s

We need to find the kinetic energy of the projectile. We know that the formula for the kinetic energy of an object is given by :

`K=(1)/(2)mv^2\\\\\text{Putting all the values, we get}\\\\K=(1)/(2)* 2* (200)^2\\\\K=40000\ J`

or

`K=4* 10^4\ J`

So, the kinetic energy of the projectile will be
`4* 10^4\ J`.