74.4k views
4 votes
Consider a double Atwood machine constructed as follows: A mass 4m is suspended from a string that passes over a massless pulley on frictionless bearings. The other end of this string supports a second similar pulley, over which passes a second string supporting a mass of 3m at one end and m at the other. Using two suitable generalized coordinates, set up the Lagrangian and use the Lagrange equations to find the acceleration of the mass 4m when the system is released. Explain why the top pulley rotates even though it carries equal weights on each side.

2 Answers

1 vote

Final answer:

To find the acceleration of the 4m mass in the double Atwood machine, set up the Lagrangian using two suitable generalized coordinates. Solve the equations of motion to find the values of the tensions and accelerations. The top pulley rotates because the tensions in the two strings connected to it are different.

Step-by-step explanation:

To set up the Lagrangian for the double Atwood machine, we need to define two suitable generalized coordinates. Let's use the vertical positions of the two masses as our generalized coordinates. Let y_1 be the position of the 3m mass and y_2 be the position of the 4m mass.

The Lagrangian is given by L = T - V, where T is the kinetic energy and V is the potential energy. The kinetic energy is T = (1/2)m(v_1^2 + v_2^2), where v_1 and v_2 are the velocities of the masses. The potential energy is V = mg(y_1 + y_2).

Using the Lagrange equations, we can find the equations of motion for the generalized coordinates. The equation for y_1 is m(ay_1'' - g) = 3mg - T_1, where T_1 is the tension in the string connected to the 3m mass. The equation for y_2 is 4m(ay_2'' - g) = T_1 - T_2, where T_2 is the tension in the string connected to the 4m mass.

To find the acceleration of the 4m mass when the system is released, we need to solve the equations of motion. Solving these equations will give us the values of T_1, T_2, and the accelerations y_1'' and y_2''. Finally, we can find the acceleration of the 4m mass by substituting the values into the equation for y_2''.

The top pulley rotates even though it carries equal weights on each side because the tensions in the two strings connected to the pulley are different. This creates a net torque on the pulley, causing it to rotate.

User Kadejiah
by
5.3k points
3 votes

Answer:

Hello your question is incomplete attached below is the complete question

Answer : x ( acceleration of mass 4m ) =
(g)/(7)

The top pulley rotates because it has to keep the center of mass of the system at equilibrium

Step-by-step explanation:

Given data:

mass suspended = 4 meters

mass suspended at other end = 3 meters

first we have to express the kinetic and potential energy equations

The general kinetic energy of the system can be written as

T =
(4m)/(2) x^2 + (3m)/(2) (-x+y)^2 + (m)/(2) (-x-y)^2

T =
4mx^2 + 2my^2 -2mxy

also the general potential energy can be expressed as

U =
-4mgx-3mg(-x+y)-mg(-x-y)+constant=-2mgy +constant

The Lagrangian of the problem can now be setup as


L =4mx^2 +2my^2 -2mxy +2mgy + constant

next we will take the Euler-Lagrange equation for the generalized equations :

Euler-Lagrange equation =
4x-y =0\\-2y+x +g = 0

solving the equations simultaneously

x ( acceleration of mass 4m ) =
(g)/(7)

The top pulley rotates because it has to keep the center of mass of the system at equilibrium

Consider a double Atwood machine constructed as follows: A mass 4m is suspended from-example-1
User Wkm
by
4.7k points