Question

3 consecutive odd integers such that the sum of twice the first and three times the second is 55 more than twice the third

Answer 1

Consecutive odd integers are 19 , 21 & 23

Explanation:

Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).

According to the question,

`2x + 3(x + 2) = 2(x + 4) + 55`

`= > 2x + 3x + 6 = 2x + 8 + 55`

Eliminating 2x from both the sides,

`= > 3x + 6 = 63`

`= > 3x = 63 - 6 = 57`

`= > x = (57)/(3) = 19`

So, the consecutive odd integers are = 19 , 21 & 23.