Question

The emf of the battery is 1.5 V. In Nichrome there are 9 × 1028 mobile electrons per m3, and the mobility of mobile electrons is 7 × 10−5 (m/s)/(N/C). Each thick wire has length 29 cm = 0.29 m and cross-sectional area 9 × 10−8 m2. The thin wire has length 6 cm = 0.06 m and cross-sectional area 1.3 × 10−8 m2. (The total length of the three wires is 64 cm.) In the steady state, calculate the number of electrons entering the thin wire every second. Do not make any approximations, and do not use Ohm's law or series-resistance equations.

Answer 1

To calculate the number of electrons entering the thin wire every second, we need to use the formula I = nqAvd. However, in this question, the drift velocity is not given, so we cannot calculate the number of electrons without using Ohm's law or series-resistance equations.

Step-by-step explanation:

To calculate the number of electrons entering the thin wire every second, we can use the formula I = nqAvd, where I is the current, n is the number density of charge carriers, q is the charge of an electron, A is the cross-sectional area, and vd is the drift velocity. In this case, the current is given as 1.5 V. The number density of electrons in Nichrome is 9 × 10^28 electrons per m^3. The cross-sectional area of the thin wire is given as 1.3 × 10^(-8) m^2. The drift velocity is not given, so we cannot calculate the number of electrons entering the thin wire every second without using the Ohm's law or series-resistance equations, which is not allowed in this question.