Answer:
The duration is
![T =72 \ years /tex]</p><p>Explanation:</p><p>From the question we are told that </p><p> The distance is [tex]D = 35 \ light-years = 35 * 9.46 *10^(15) = 3.311 *10^(17) \ m](https://img.qammunity.org/2021/formulas/physics/college/g4wac9n8r6aa5aahxxdfzexa1ia6nlyliz.png)
Generally the time it would take for the message to get the the other civilization is mathematically represented as
![t = (D)/(c)](https://img.qammunity.org/2021/formulas/physics/college/qkbywfhg25t26n97kyqjx8ty5rl7ipp8g6.png)
Here c is the speed of light with the value
![c = 3.08 *10^(8) \ m/s](https://img.qammunity.org/2021/formulas/physics/college/hqdz257yyaj7bncwpsmg6g6zb6kj5j285x.png)
=>
![t = (3.311 *10^(17) )/(3.08 *10^(8))](https://img.qammunity.org/2021/formulas/physics/college/vxlihth7mby6v5kdrbu3tuc0tr1gq31v1w.png)
=>
![t = 1.075 *10^9 \ s](https://img.qammunity.org/2021/formulas/physics/college/6rrphndlfpxkmjgqt1qw03albfwm4ri64u.png)
converting to years
![t = 1.075 *10^9 * 3.17 *10^(-8)](https://img.qammunity.org/2021/formulas/physics/college/k38e3w39t8rby4pzak2wfngwems3jnvoos.png)
![t = 1.075 *10^9 * 3.17 *10^(-8)](https://img.qammunity.org/2021/formulas/physics/college/k38e3w39t8rby4pzak2wfngwems3jnvoos.png)
![t = 34 \ years](https://img.qammunity.org/2021/formulas/physics/college/qticcocdp03xfgwpq6aft8yx504ltqukfw.png)
Now the total time taken is mathematically represented as
![T = 2* t + 2 + 2](https://img.qammunity.org/2021/formulas/physics/college/gaiyy4z1ue8gp6zobwcniqlfkpon0jkytw.png)
=>
![T = 2* 34 + 2 + 2](https://img.qammunity.org/2021/formulas/physics/college/lfxd5iaw2nvj2otkh0vc0x2kda1olkdoui.png)
=> [tex]T =72 \ years /tex]