Question

Based on the survey results from 300 selected students in the Burbank School District (BSD), the 98% confidence interval used to estimate the population proportion of all BSD students who have access to a working computer at home was computed to be 48% to 60%. The following 2 subquestions require a numeric input, no work is necessary. [2 points] What number of students (out of the 300 sampled) have access to a working computer at home

Answer 1

follows are the solution to this question:

Explanation:

Please find the correct question in the attached file:

The formula for calculating the Confidence interval of proportion:

`\to CI=\hat{p} \pm Z_{(\alpha)/(2)} \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\\\\\to \hat{p}=\frac{\text{lower limit +upper limit}}{2}\\`

`=(0.48+0.60)/(2)\\\\=(1.08)/(2)\\\\=0.54`

The number of learners with access to working at home on a computer:

`= 0.54 * 300 \\\\=162`

Lower limit =0.48

upper limit = 0.60

`\to margin \ error = \frac{\text{upper limit - lower limit}}{2}\\`

`=(0.60-0.48)/(2)\\\\=(0.12)/(2)\\\\= 0.06`