Explanation:
Hey there!
Here;
ABC is a Right angled triangle.
Taking reference angle as angleA.
Now;
Hypotenuse (h) = AB
Perpendicular (BC)= 24 ft.
Base(AC)= 10 ft.
Now, Using Pythagoras relation;
![h = \sqrt{ {p}^(2) + {b}^(2) }](https://img.qammunity.org/2021/formulas/mathematics/middle-school/154legj29zd5824e2bkudk4mhy16ely3kl.png)
Put all values.
![h = \sqrt{ {24}^(2) + {10}^(2) }](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ei8f000yo2rn7wrseijcijqkn00brbfa87.png)
Simplify it.
![h = √(576 + 100)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/h46vzj4dhhpthge8wgi7y3unodyogtuswh.png)
![h = √(676)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8odn6xssh5k44ps7m7suarhullxqyky478.png)
Therefore, h= 26ft.
ANS: OPTION A.
Hope it helps....