Question

It takes 525 J of work to compress a spring 25 cm. What is the force constant of the spring (in kN/m)?

Answer 1

1.680kN/m

Step-by-step explanation:

Work done by the spring is expressed as shown:

`W = (1)/(2)ke^2` where:

k is the spring constant

e is the extension

Given

W = 525Joules

extension = 25cm = 0.25m

Substitute into the formula:

`525 = (1)/(2)k(0.25)^(2) \\525 = (0.0625k)/(2)\\ 525 = 0.03125k\\k = (525)/(0.3125)\\k = 1680N/m\\k = 1.680kN/m`

Hence the force constant of the spring is 1.680kN/m