Answer:
0.8152 ≤ p ≤ 0.8608
579
Explanation:
Given the following :
Samples size n = 1000
Deaths within 10 years, p = 838
α = 95%
Construction a two way confidence interval:
p ± Zα/2 * √p(1-p) / n
point estimate p = 838/n = 838/1000 = 0.838
Z0.05/2 = Z0.025 = 1.96
0.838 - 1.96√0.838(1-0.838) / 1000
0.838 - 1.96*0.0116514 = 0.8152
0.838 + 1.96√0.838(1-0.838) / 1000
0.838 + 1.96*0.0116514 = 0.8608
0.8152 ≤ p ≤ 0.8608
b) Using the point estimate of p obtained from the preliminary sample, what sample size is needed to be 95% confident that the error in estimating the true value of p is less than 0.03
Error (E) = 0.03
To find the samome size, use the relation:
n = (Zα/2 / E)² * p(1-p)
n = (1.96/0.03)² * 0.838(1-0.838)
n = (1.96/0.03)² * 0.838 * 0.162
n = 4268.4444 * 0.838 * 0.162
n = 579.46
n = 579