Question

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $60. For one performance, 40 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $2200. What was the price of each kind of ticket?

Answer 1

Answer: price of advance ticket = $40

and price of same day ticket= $20

Step-by-step explanation:

let one advance ticket be x

let one same day ticket be y

The combined cost of one advance ticket and one same-day ticket is $60

so we have that

x + y = $60

For one performance, 40 advance tickets and 30 same-day tickets were sold of which the tota;l amount was $2,200

40x +30y= 2220

we have

x + y = $60... eqn 1

40x +30y= 2220... eqn 2

by substitution,

x+y = 60

y = 60-x

putting the value of y in equation 2

40x + 30(60-x) =2200

40x + 1800-30x=2200

40x-30x= 2200-1800

10x=400

x = 400/10 = 40

to get y

x+y =60

40 + y=60

y = 60-40 =20

Therefore price of advance ticket,x = $40

and price of same day ticket, y = $20