Answer:
Null hypothesis:
![\mathbf{H_o: \mu = 444}](https://img.qammunity.org/2021/formulas/mathematics/college/cdmd0ajl7ch0nt1juvzhegsnba9i0pviro.png)
Alternative hypothesis:
![\mathbf{H_1: \mu < 444}](https://img.qammunity.org/2021/formulas/mathematics/college/v0v5nw8covg5ol49vumpnkimcvocuxfsva.png)
Explanation:
From the given information:
the population mean = 444
the sample mean = 443
number of samples = 40
standard deviation = 23
The null hypotheses and he alternative hypotheses can be computed as:
Null hypothesis:
![\mathbf{H_o: \mu = 444}](https://img.qammunity.org/2021/formulas/mathematics/college/cdmd0ajl7ch0nt1juvzhegsnba9i0pviro.png)
Alternative hypothesis:
![\mathbf{H_1: \mu < 444}](https://img.qammunity.org/2021/formulas/mathematics/college/v0v5nw8covg5ol49vumpnkimcvocuxfsva.png)
Thus, this is left-tailed since the alternative hypothesis is less than the population mean
The test statistics can be computed as follows:
![Z = (\overline x - \mu )/((\sigma)/(√(n)))](https://img.qammunity.org/2021/formulas/mathematics/college/vmcg0flvggh97247q5dn6n9q0jd3esl0pa.png)
![Z = (443 - 444 )/((23)/(√(40)))](https://img.qammunity.org/2021/formulas/mathematics/college/ed3u271okur9ypsj97j143yal58aqlw552.png)
Z = - 0.275
At the level of significance of 0.02;
the critical value of
![Z_(\alpha/2) = Z_(0.02/2)=-2.05](https://img.qammunity.org/2021/formulas/mathematics/college/j1pw4nhkt6p4rprfvrx26buac5yzqpgra3.png)
Decision rule: To reject the null hypothesis if the value of the Z score is lesser than the critical value.
Conclusion:
We fail to reject the null hypothesis and we conclude that sufficient evidence to support the claim that the machine bags were underfilled.