81.8k views
2 votes
Travel time data is collected on an arterial. With 30 runs, an average travel time of 152 seconds is computed over the 2.0 miles length, with a computed standard deviation of 17.3 seconds.

Required:
a. Compute 95% confidence bounds on your estimate of the mean.
b. Was it necessary to make any assumption about the shape of the travel-time distribution?

User Seanrco
by
6.4k points

1 Answer

5 votes

Answer:

a

The 95% confidence bounds is
145.80 < &nbsp;\mu < &nbsp; 158.19

b

It was not necessary to make any assumption about the shape of the travel time distribution

Explanation:

From the question we are told that

The sample size is n = 30

The sample mean is
\=x = 152

The standard deviation is
\sigma = 17.3 \ second

From the question we are told the confidence level is 95% , hence the level of significance is


\alpha = (100 - 95 ) \%

=>
\alpha = 0.05

Generally from the normal distribution table the critical value of
(\alpha )/(2) is


Z_{(\alpha )/(2) } = &nbsp;1.96

Generally the margin of error is mathematically represented as


E = Z_{(\alpha )/(2) } * &nbsp;(\sigma )/(√(n) )

=>
E = &nbsp;1.96 * &nbsp;(17.3 )/(√(30) )

=>
E = 6.19

Generally 95% confidence bounds is mathematically represented as


\= x -E < &nbsp;\mu < &nbsp;\=x &nbsp;+E

=>
152 &nbsp;-6.19 < &nbsp;\mu < &nbsp;152 &nbsp;-6.19

=>
145.80 < &nbsp;\mu < &nbsp; 158.19

This 95% confidence bounds show that there is 95% confidence that the true mean lies within this bound hence there is it was not necessary to make any assumption about the shape of the travel time distribution

User Nikhil Kamani
by
6.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.