Answer:
0.0128
Explanation:
(Use technology and enter your answer rounded to four decimal places.)
We apply the z score formula to this question
z = (x-μ)/σ,
where x is the raw score
μ is the population mean
σ is the population standard deviation.
We are given: N(2750,560)
x = 1500 grams, μ = 2750 grams, σ = 560 grams
= z = 1500 - 2750/560
z = -2.23214
Determining the Probabilty value from Z-Table:
P(x < 1500) = P(z = -2.23214)
= 0.012803
Approximately to four decimal places = 0.0128
The probability that a randomly chosen late-preterm baby would have a very low birth weight, less than 1500 grams is 0.0128.