Answer:
The fractional saturation for hemoglobin is 0.86
Step-by-step explanation:
The fractional saturation for hemoglobin can be calculated using the formula

Where
is the fractional oxygen saturation
is the partial pressure of oxygen
is the partial pressure when 50% hemoglobin is saturated with oxygen
and h is the Hill coefficient
From the question,
= 40 mm Hg
= 22 mm Hg
h = 3
Putting these values into the equation, we get





Hence, the fractional saturation for hemoglobin is 0.86.