Question

Let x be a discrete random variable that possesses a binomial distribution with n=5 and p=0.87. What are the mean and standard deviation of this probability distribution? Round your answers to three decimal places, if required.

Answer 1

`Mean = 4.35`

`SD = 0.5655`

Explanation:

Given

`n = 5`

`p = 0.87`

Solving (a): Mean

`Mean = np`

`Mean = 5 * 0.87`

`Mean = 4.35`

Solving (b): Standard Deviation (SD)

`SD = np(1 - p)`

`SD = 5 * 0.87(1 - 0.87)`

`SD = 5 * 0.87 * 0.13`

`SD = 0.5655`