Question

Laura is planning a party for her son. She has $50 dollars remaining in her budget and wants to provide one party favor per person to at least 10 guests. She found some miniature stuffed animals for $6.00 each and some toy trucks for $4.00 each. Which system of inequalities represents this situation, where x is the number of stuffed animals and y is the number of toy trucks?

Answer 1

6x + 4y ≤ 50: This inequality represents the budget constraint. The left-hand side (6x + 4y) represents the total cost of x stuffed animals (each costing $6) and y toy trucks (each costing $4). The inequality states that the total cost of the party favors should be less than or equal to the remaining budget, which is $50.

x + y ≥ 10: This inequality ensures that Laura provides at least 10 party favors. The left-hand side (x + y) represents the total number of party favors (stuffed animals and toy trucks). The inequality states that the total number of party favors should be greater than or equal to 10.

Final answer: 6x + 4y ≤ 50

x + y ≥ 10

Answer 2

The system of inequalities that represents this situation is:

x+y≥10

6x+4y≤50

Explanation:

As the statement says that Laura wants to provide one party favor per person to at least 10 guests, the first inequality would indicate that the number of stuffed animals plus the number of toy trucks should be equal or greater than 10:

x+y≥10

Also, the statement indicates that miniature stuffed animals cost $6.00 each and the toy trucks cost $4.00 each and that Laura has $50. From this, you would have an inequality that indicates that 6 for the number of miniature stuffed animals and 4 for the number of toy trucks would be equal or less than 50:

6x+4y≤50

The answer is that the system of inequalities that represents this situation is:

x+y≥10

6x+4y≤50