Question

Is it true or false that the displacement always equals the product of the average velocity and the time interval?

Answer 1

True.

Step-by-step explanation:

• Applying the definition of average velocity, we know that we can always write the following expression:

`v_(avg) = (\Delta x)/(\Delta t)` (1)

• By definition, Δx is just the displacement, and Δt is the time interval.
• So, just rearranging terms in (1), we get:

`\Delta x} = v_(avg)* {\Delta t}`