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A 1 kg object is located at a distance of 1.0 x 103 m from the center of a larger

object whose mass is 2.0 x 1020 kg.
a. What is the size of the force acting on the smaller object?

User Fanton
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1 Answer

4 votes

The force = 1.334 x 10⁴ N

Further explanation

Gravity is a force that arises because of the attraction between objects with mass.

The magnitude of this attraction is proportional to the mass of the object.

The greater the mass of the object, the greater the gravitational force

Relationships can both be stated in

Newton's Gravity Law:


\rm F=G.(m_1.m_2)/(r^2)

with F = gravitational force, N

G = gravitational constant, 6.67 x 10⁻¹¹ Nm²/kg²

m1, m2 = mass of object, kg

r = distance between two objects. m

m₁= 1 kg

m₂=2 x 10²⁰ kg

r = 1 x 10³ m

The force acting on the smaller object=The force acting on the larger object(Newton's Third Law)


\tt F=6.67* 10^(-11)(1* 2.10^(20))/((1* 10^3)^2)\\\\F=1.334* 10^4~N

User Ori Yarden PhD
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