Answer:
The image of the point (0, -6) under the same translation is (-6, -12)
Explanation:
Let us revise the rules of translation
- If the point (x, y) translated horizontally to the right by h units then its image is (x + h, y) ⇒ T (x, y) → (x + h, y)
- If the point (x, y) translated horizontally to the left by h units then its image is (x - h, y) ⇒ T (x, y) → (x - h, y)
- If the point (x, y) translated vertically up by k units then its image is (x, y + k)→ (x + h, y) ⇒ T (x, y) → (x, y + k)
- If the point (x, y) translated vertically down by k units then its image is (x, y - k) ⇒ T (x, y) → (x, y - k)
∵ The coordinate of point P are (3, 8)
∵ The coordinates of its image P' are (-3, 2)
→ The x-coordinate is changed from 3 to -3, that means the point
translated to the left by h units
∵ h = -3 - 3
∴ h = -6
→ The y-coordinate is changed from 8 to 2, that means the point
translated down by k units
∵ k = 2 - 8
∴ k = -6
→ By using the rule above
∴ The rule of translation is (x, y) → (x - 6, y - 6)
∵ The coordinates of the point are (0, -6)
∴ The coordinates of its image are (0 - 6, -6 - 6)
∴ The coordinates of its image are (-6, -12)