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Actual roots of f(x)=2x^2+2x-24

2 Answers

5 votes

Answer:

x= 3, -4

Explanation:

Set 2 x ² + 2 x − 24 equal to 0 .

2 x ² + 2 x − 24 = 0

Solve for x .

Factor the left side of the equation.

2 ( x² + x − 12 ) = 0

Factor

x ² + x − 12 using the AC method.

2 ( x − 3 ) ( x + 4 ) = 0

If any individual factor on the left side of the equation is equal to 0 , the entire expression will be equal to 0 .

x − 3 = 0

x + 4 = 0

Add 3 and subtract 4 to both sides of the equation.

x = 3

x = -4

User Justin Ngan
by
7.8k points
6 votes


f(x) = 2 {x}^(2) + 2x - 24


f(x) = 2( {x}^(2) + x - 12)


0 = 2( {x}^(2) + x - 12)

Divided sides by 2


{x}^(2) + x - 12 = 0


(x + 4)(x - 3) = 0

_________________________________


x + 4 = 0


x = - 4

_________________________________


x - 3 = 0


x = 3

Thus the actual roots are -4 and 3.....

And we're done.

♥️♥️♥️♥️♥️

User Mtomy
by
8.0k points

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