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A motorbike accelerates with a force of 15000N. It experiences air resistance which acts in the opposite direction with a magnitude of 1200N. Calculate the unbalanced force that is acting on the motorbike.

User Btleffler
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2 Answers

2 votes

Answer:

13800N

Step-by-step explanation:

15000N is the force of motorbike

1200N is air resistance in opposite direction

15000N-1200N=13800N

User Synox
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5 votes

Answer:

Ft = 13800 [N]

Step-by-step explanation:

We have to carry out a force analysis and assume the directions of those forces. First the force that causes the movement of the rider is equal to 15000 [N] and is directed to the right. Since the resistance of the air is opposite to the movement, it generates a resistance with a value of 1200 [N], with direction to the left. However, the rider continues to move to the right, as the force generated by the bike is greater, i.e. this force must be to the right for movement to exist. By means of a summation of forces on the X axis we can calculate the value of the resulting force. The forces to the right will be taken with a positive sign and the forces to the left with a negative sign.

15000 - 1200 = Ft

where:

Ft = unbalanced force [N]

Ft = 13800 [N]

User Mdunisch
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