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Using the table from Question 7, select 1 other possible representation,
4
Of(-1) =1
f(n) = f(n-1)-2
Of(-1) = 1
f(n) = f (n − 1) +
Of(-1) = 1
f(n) = f(n-1) + 2
of(-1) = 1
f(n) = f (2) - n-1

User Brian Fox
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Answer:

1,7 so you can do add to get to it

User Zaheer Ul Hassan
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