Question

6.82

A 2.10-mole sample of crystalline acetic acid, ini-

tially at 17.0°C, is allowed to melt at 17.0°C and is

then heated to 118.1°C (its normal boiling point) at

1.00 atm. The sample is allowed to vaporize at.

118.1°C and is then rapidly quenched to 17.0°C, so

that it recrystallizes. Calculate AH° for the total pro-

cess as described.

Answer 1

0 kj

Step-by-step explanation:

melting/initial temperature = 17.0°c

boiling point = 118.1°C

pressure = 1.00 atm

2.10 mole sample of crystalline

attached below is the detailed solution required